JEE MAIN - Physics (2020 - 9th January Morning Slot - No. 1)
In a fluorescent lamp choke (a small
transformer) 100 V of reverse voltage is
produced when the choke current changes
uniformly from 0.25 A to 0 in a duration of
0.025 ms. The self-inductance of the choke
(in mH) is estimated to be ________.
پاسخ دهید
10
توضیح
V = $$\left| {L{{di} \over {dt}}} \right|$$
$$ \Rightarrow $$ L = $${V \over {\left| {{{di} \over {dt}}} \right|}}$$ = $${{100} \over {{{0.25} \over {0.025 \times {{10}^{ - 3}}}}}}$$ = 10 mH
$$ \Rightarrow $$ L = $${V \over {\left| {{{di} \over {dt}}} \right|}}$$ = $${{100} \over {{{0.25} \over {0.025 \times {{10}^{ - 3}}}}}}$$ = 10 mH